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The second minimum in the diffraction pattern of a .1 mm wide slit occurs at .7. What is the wavelength?

User Jeriko
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Final answer:

The question asks for the wavelength of light based on the second minimum in a diffraction pattern from a slit but lacks sufficient details for an exact answer.

Step-by-step explanation:

The question is seeking to determine the wavelength of light that corresponds to the second minimum in a diffraction pattern created by a slit of a given width. According to the formula for the minima in a single-slit diffraction pattern, d sin(\theta) = m\lambda, where d is the slit width, \theta is the angle of the minimum, m is the order number of the minimum, and \lambda is the wavelength.

To solve for the wavelength \lambda, the angle \theta can be determined from the provided information about the position of the second minimum and the slit width. However, the question does not provide enough details, such as the distance between the slit and screen or the exact angle \theta, which is essential to calculate \lambda. More information is needed to provide an accurate answer.

User Snugug
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