Final answer:
The final temperature of the water, after adding a hot piece of iron that transferred 45755 J of energy to it, is 23.65 °C.
Step-by-step explanation:
To find the final temperature of the water after 45755 J of energy is transferred from the hot piece of iron, we use the formula for heat transfer q = mcΔT, where q is the heat transferred, m is the mass of the water, c is the specific heat, and ΔT is the change in temperature.
Since we know the water's mass (3000 g), its initial temperature (20.0 °C), and the specific heat of water (4.184 J/g °C), as well as the energy transferred, we can solve for the final temperature of the water.
Using the formula:
q = (3000 g) × (4.184 J/g °C) × (ΔT)
45755 J = (3000 g) × (4.184 J/g °C) × (ΔT)
ΔT = 45755 J / ((3000 g) × (4.184 J/g °C))
ΔT = 45755 J / 12552 J/°C
ΔT = 3.65 °C
The final temperature of the water is thus the initial temperature plus the change in temperature:
Final temperature = 20.0 °C + 3.65 °C
Final temperature = 23.65 °C