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Write an equation of the line in slope-intercept form that passes through (-3,-6) and is parallel to y = -5x + 1?

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Final answer:

To find the equation of a line parallel to y = -5x + 1 passing through (-3,-6), we use the same slope of -5 and plug the point into the slope-intercept form to find the y-intercept. The resulting equation is y = -5x - 21.

Step-by-step explanation:

The question asks to find the equation of a line that is parallel to a given line and passes through a specific point.

The given line is y = -5x + 1, which means its slope, m, is -5. Since parallel lines have the same slope, the line we are looking for will also have a slope of -5.

To find the y-intercept, b, we can use the point (-3, -6) and the slope -5 in the slope-intercept form y = mx + b. Plugging in the values we get:

  • y = -5x + b
  • -6 = -5(-3) + b
  • -6 = 15 + b
  • b = -6 - 15
  • b = -21

So the equation of the line is y = -5x - 21.

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