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9. Un coche de carreras tiene una velocidad inicial de 4 m/s al sur y

experimenta una aceleración de 2 m/s², la cual dura 12 segundos.
Calcula:
a) ¿Qué desplazamiento tiene a los 12 segundos?
b) ¿Qué velocidad lleva a los 12 segundos?

1 Answer

4 votes

At 12 seconds, the car has a displacement of 120 meters south, and its velocity is 28 m/s.

a) To find the displacement, you can use the kinematic equation
: \( s = ut + (1)/(2)at^2 \), where
\( s \) is displacement,
\( u \) is initial velocity,
\( a \) is acceleration, and
\( t \) is time.


\( s = (4 \,
\text{m/s})(12 \,
\text{s}) + (1)/(2)(2 \,
\text{m/s}^2)(12 \,
\text{s})^2 \)\( s = 48 \,
\text{m} + 72 \,
\text{m} \)\( s = 120 \,
\text{m} \)

So, the displacement at 12 seconds is 120 meters.

b) To find the final velocity, use the equation:
\( v = u + at \), where
\( v \) is final velocity.


\( v = (4 \,
\text{m/s}) + (2 \,
\text{m/s}^2)(12 \,
\text{s}) \)\( v = 4 \,
\text{m/s} + 24\,
\text{m/s} \)\( v = 28 \,
\text{m/s} \)

Question:

9. A racing car has an initial velocity of 4 m/s south and undergoes an acceleration of 2 m/s², which lasts for 12 seconds. Calculate:

a) What displacement does it have at 12 seconds?

b) What velocity does it have at 12 seconds?

User Meeta
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