Final answer:
The foci of an elliptical whispering gallery can be found using the formula c = sqrt(a^2 - b^2), where a is the semi-major axis and b is the semi-minor axis of the ellipse. In this case, the hall is 110 ft in length and the ceiling is 40 ft high at the center. Therefore, the foci of the ellipse are approximately 51.24 ft from the center.
Step-by-step explanation:
The foci of an elliptical whispering gallery can be found using the formula:
c = sqrt(a^2 - b^2)
where a is the semi-major axis and b is the semi-minor axis of the ellipse. In this case, the length of the ellipse is the semi-major axis and the height of the center is the semi-minor axis.
Given that the hall is 110 ft in length and the ceiling is 40 ft high at the center, we can calculate the semi-major axis (a) as 55 ft and the semi-minor axis (b) as 20 ft. Plugging these values into the formula, we get:
c = sqrt(55^2 - 20^2)
c = sqrt(3025 - 400)
c = sqrt(2625)
c ≈ 51.24 ft
Therefore, the foci of the ellipse are approximately 51.24 ft from the center.