199k views
4 votes
a passenger on a train approaching a station at 29 m/s hears a bell ringing in the station. take the speed of sound to be 343 m/s----------------------

1 Answer

2 votes

Final answer:

The speed of the train can be calculated using the formula for the Doppler effect. Therefore, the frequency heard by the observer as the train moves away is approximately 4.314 times the original frequency.

Step-by-step explanation:

When a train approaches a crossing, the frequency of the sound heard by an observer changes due to the Doppler effect. The Doppler effect describes the change in frequency and wavelength of a wave as the source and observer move relative to each other.

(a) To find the speed of the train, we can use the formula for the Doppler effect:

Δf/f = v/(v±vs)

Where Δf is the change in frequency, f is the original frequency, v is the velocity of sound, and vs is the velocity of the source (train). Rearranging the formula to solve for vs:

vs = v(1 - f/Δf)

Substituting the given values:

vs = 343(1 - 208/888)

vs ≈ 343(1 - 0.234)

vs ≈ 343(0.766)

vs ≈ 263.438 m/s

Therefore, the speed of the train is approximately 263.438 m/s.

(b) To find the frequency heard by the observer as the train moves away, we can use the same formula, but with a negative sign:

Δf/f = v/(v ± vs)

Substituting the given values:

Δf/f = 343/(343 ± 263.438)

Δf/f ≈ 343/79.562

Δf/f ≈ 4.314

Δf ≈ 4.314f

Therefore, the frequency heard by the observer as the train moves away is approximately 4.314 times the original frequency.

User Nuzhny
by
8.1k points