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a parallel-plate capacitor is formed from two 6.4-cm-diameter electrodes spaced 2.2 mm apart. the electric field strength inside the capacitor is 2.0×106n/c.-----------------

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Final answer:

The electric field strength between the plates of a parallel-plate capacitor can be found using the formula E = V/d, where E is the electric field strength, V is the potential difference, and d is the separation distance. Using the given information and formula, the potential difference is calculated to be 4400 V.

Step-by-step explanation:

A parallel-plate capacitor is formed from two 6.4 cm diameter electrodes spaced 2.2 mm apart. To find the electric field strength between the plates, we can use the formula:

E = V/d

where E is the electric field strength, V is the potential difference between the plates, and d is the separation distance between the plates. In this case, the electric field strength is given as 2.0 x 10^6 N/C. By rearranging the formula, we can solve for V:

V = E * d = (2.0 x 10^6 N/C) * (2.2 x 10^-3 m) = 4400 V

Therefore, the potential difference between the plates is 4400 V.

User Ross Goddard
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