Question

the equilibrium concentrations were found to be [nh3]=0.250 m , [h2]=0.490 m , and [n2]=0.800 m . what is the equilibrium constant for this reaction?

Answer 1

The equilibrium constant for this reaction is 0.0324.

Step-by-step explanation:

The equilibrium constant (Kc) is determined by dividing the concentration of products by the concentration of reactants, each raised to the power of their stoichiometric coefficient in the balanced equation. In this case, for the reaction N2(g) + 3H2(g) -> 2NH3(g), the equilibrium constant would be [NH3]^2 / [N2][H2]^3. Plugging in the given equilibrium concentrations, the equilibrium constant can be calculated as (0.250 M)^2 / (0.490 M)(0.800 M)^3.

Therefore, the equilibrium constant for this reaction is 0.0324.