Question

The rate constant for the reaction is 0.170 M-1 s-1 at 200 C. A ? Products. If the initial concentration of A is 0.00630 M, what will be the concentration after 815 s?

Answer 1

To calculate the concentration of A after 815 seconds in a second-order reaction, use the integrated rate law and the given rate constant and initial concentration.

Step-by-step explanation:

The given reaction is second order. We can use the integrated rate law for a second-order reaction to calculate the concentration of A at a given time. The integrated rate law is given as:

[A] = [A0] / (1 + k[A0]t)

Where [A] is the final concentration of A, [A0] is the initial concentration of A, k is the rate constant, and t is the time.

Plugging in the given values:

[A] = 0.00630 M / (1 + (0.170 M-1 s-1)(0.00630 M)(815 s))

Solving this equation will give you the concentration of A after 815 seconds.