Question

Suppose 20.00 mL of an H₂SO₄ solution with an unknown concentration was titrated to a phenolphthalein endpoint with 37.89 mL of a 0.1005 M NaOH solution. What is the concentration of the H₂SO₄ solution?

Answer 1

To find the concentration of the H₂SO₄ solution, you can set up a proportion using the stoichiometric ratio between H₂SO₄ and NaOH. Plugging in the given values and solving for the unknown Molarity, the concentration of the H₂SO₄ solution is 0.190 M.

Step-by-step explanation:

In order to determine the concentration of the H₂SO₄ solution, we can use the equation:

H₂SO4(aq) + 2NaOH(aq) → Na₂SO₄(aq) + 2H₂O(l)

By comparing the stoichiometric ratio between H₂SO₄ and NaOH, we can set up a proportion to calculate the concentration:

(Molarity of NaOH) × (Volume of NaOH) = (Molarity of H₂SO₄) × (Volume of H₂SO₄)

Plugging in the given values:

(0.1005 M) × (37.89 mL) = (unknown M) × (20.00 mL)

Solving for the unknown Molarity:

(0.1005 M) × (37.89 mL) ÷ (20.00 mL) = 0.190 M