Final answer:
The discrete-time system described is not memoryless.
Step-by-step explanation:
Memoryless systems are those where the output at a given time depends only on the input at that same time and does not depend on any past inputs or outputs.
In this case, the output y[n] is determined by the current input x[n] and the input two steps earlier, x[n-2]. Since the output relies on past inputs, the system is not memoryless.
For example, if x[0] = 3 and x[-2] = 2, then y[0] = x[0] * x[0-2] = 3 * 2 = 6.