Question

the jamison family kept a log of the distance they traveled during a trip as represented by the graph below during which interval was their average speed the greatest

Answer 1

The greatest average speed occurs during the interval from the 1st to the 2nd hour, which corresponds to option (1).

To determine the average speed during each interval, you can use the formula:

Average Speed =
`(Change in Distance)/(Change in Time)`

Let's calculate the average speeds for each interval:

Average Speed (1st to 2nd hour) =
`(110- 40)/(2 - 1) =(70)/(1) =70`

Average Speed (2nd to 4th hour) =
`(180- 110)/(4 - 2) =(70)/(2) = 35`

Average Speed (6th to 8th hour)=
`(350- 230)/(8-6) = (120)/(2) = 60`

Average Speed (8th to 10th hour) =
`(390- 350)/(10-8) =(40)/(2) =20`

Therefore, the greatest average speed occurs during the interval from the 1st to the 2nd hour, which corresponds to option (1).

Question

The Jamison family kept a log of the distance they traveled during a trip, as represented by the graph below.

distance

(1,40)

(2,110)

(4,180)

(6,230)

(8,350)

(10,390)

Elapsed Time (hours)

During which interval was their average speed the greatest?

(1) the first hour to the second hour

(2) the second hour to the fourth hour

(3) the sixth hour to the eighth hour

(4) the eighth hour to the tenth hour