Final answer:
The order of steps to prove that 7n + 4 is even if n is even involves expressing n as 2k, substituting into 7n + 4, distributing 7, factoring out 2, and showing the result is 2 times an integer.
Step-by-step explanation:
To prove that if n is even, then 7n + 4 is even, we must put the steps in the correct order:
- Since n is even, it can be written as 2k for some integer k.
- Then 7n + 4 can be rewritten using the substitution n = 2k, which gives us 7(2k) + 4.
- By distributing 7 across the parentheses, we have 14k + 4.
- Now we can factor out a 2, resulting in 2(7k + 2).
- This is 2 times an integer, so it is even.
By following these steps, we can easily demonstrate that if n is even, 7n + 4 will also be even, as it can be expressed in the form 2m, where m is an integer.