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Two 23.0 ml samples, one 0.100 moll-1 HCl and the other 0.100 moll-1 HF, were titrated with 0.200 moll-1 KOH. What is the volume of added base at the equivalence point for HCl?

User ChessMax
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1 Answer

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Final answer:

The volume of added base at the equivalence point for HCl is 23.0 mL.

Step-by-step explanation:

The volume of added base at the equivalence point for HCl in this titration can be determined by using the stoichiometry of the reaction between HCl and KOH. The balanced equation for this reaction is:

HCl + KOH -> KCl + H2O

From the equation, we can see that the stoichiometric ratio between HCl and KOH is 1:1. Therefore, the volume of added base at the equivalence point for HCl is equal to the volume of HCl used in the titration, which is 23.0 mL.

User Laurent Legrand
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