Question

Please help me thank you so much

Answer 1

Solving for d :

» We're gonna use the sine trigonometric ratios angle 60°

`{ \tt{ \sin( \theta) = (opposite)/(hypotenuse) }} \\ \\ { \tt{ \sin(60 \degree) = (d)/(2) }} \\ \\ { \tt{d = 2 * \sin(60 \degree) }} \\ { \tt{d = 2 * ( √(3) )/(2) }} \\ \\ { \boxed{ \tt{ \: d = √(3) } \: }}`

Solving for b :

» We're gonna use cosine trigonometric ratios of angle 45°

`{ \tt{ \cos( \theta) = (adjacent)/(hypotenuse) }} \\ \\ { \tt{ \cos(45 \degree) = (b)/(4) }} \\ \\ { \tt{b = 4 * \cos(45 \degree) }} \\ { \tt{b = 4 * (1)/( √(2) ) = (4)/( √(2) ) }} \\ \\ { \tt{b = ( (4)/( √(2) )) * ( √(2) )/( √(2) ) }} \\ \\ { \tt{b = (4 √(2) )/(2) }} \\ \\ { \boxed{ \tt{ \: b = 2 √(2) \: }}}`