Question

Line segment xy has endpoints x(-10, -1) and y(5, 15). To find the y-coordinate of the point that divides the directed line segment in a 5:3 ratio, the formula v = -a b) (v2 - vi) v was used to find that v = (5/3) * (15 - (-1)) + (-1). What is the y-coordinate of the point that divides xy into a 5:3 ratio?

Answer 1

To find the y-coordinate of the point that divides the line segment xy in a 5:3 ratio, substitute the values of the endpoints into the formula (5/8) * (y2 - y1) + y1 and simplify the equation.

Step-by-step explanation:

To find the y-coordinate of the point that divides the line segment xy in a 5:3 ratio, we can use the formula:

v = (5/8) * (y2 - y1) + y1

Given that the two endpoints of xy are x(-10, -1) and y(5, 15), we can substitute these values into the formula:

v = (5/8) * (15 - (-1)) + (-1)

Simplifying this equation, we get:

v = (5/8) * 16 + (-1)

v = 10 - 1

v = 9

Therefore, the y-coordinate of the point that divides xy in a 5:3 ratio is 9.