Question

in the standard (x,y) coordinate plan, what is the radius of the center of the circle (x-5)^2 + (y+4)^2=27

Answer 1

The radius of the circle with equation (x-5)^2 + (y+4)^2 = 27 is 3√3 cm.

Step-by-step explanation:

The equation of the circle provided is (x-5)^2 + (y+4)^2 = 27. This is in the standard form of a circle's equation (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center of the circle and r is the radius. Comparing the given equation to the standard form, we can see that the radius r is the square root of 27. Therefore, the radius of the circle is √27 which simplifies to 3√3 cm.