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Find the cubic equation f(x)=ax^3+bx^2+cx+d for which f(-1)=3, f(1)=1, f(2)=6, f(3)=7

User Lautremont
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1 Answer

6 votes

f(12)+f(−8)=25,344+11,264= 36,608.

We can solve this problem by using the given information to form a system of equations and then solving for the coefficients of the polynomial.

From the given information, we know that:

f(1)=10

f(2)=20

f(3)=30

Substituting these values into the equation f(x)=x^4 +ax^3 +bx^2 +cx+d, we get:

1+a+b+c+d=10

16+8a+4b+2c+d=20

81+27a+9b+3c+d=30

We can rewrite this system of equations as a matrix equation:

| 1 | 1 | 1 | 1 | 1 | 10 |

| 16 | 8 | 4 | 2 | 1 | 20 |

| 81 | 27 | 9 | 3 | 1 | 30 |

Using Gaussian elimination, we can solve for the coefficients of the polynomial. The solution is:

a=6

b=−2

c=13

d=−10

Therefore, the polynomial is f(x)=x^4 +6x^3 −2x^2 +13x−10.

Now we can find the value of f(12)+f(−8):

f(12)=12^4 +6(12)^3 −2(12)^2 +13(12)−10=25,344

f(−8)=(−8)^4 +6(−8)^3 −2(−8)^2 +13(−8)−10=11,264

Therefore, f(12)+f(−8)=25,344+11,264= 36,608.

Question

If `f(x)=x^4+ ax^3 + bx^2 + cx + d and f(1)=10, f(2)=20, f (3)=30` then find the value of `f (12)+f(-8)`.

User Logan Wlv
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7.2k points