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Is there a value of k for which the equation 2(kx²) - 9 = 4(x - k) - 1 has infinitely many solutions? Please explain.

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Final answer:

Yes, there are values of k for which the equation has infinitely many solutions.

Step-by-step explanation:

To determine if there is a value of k for which the equation 2(kx²) - 9 = 4(x - k) - 1 has infinitely many solutions, we need to find the value of k that makes the equation true for all possible values of x. We can start by simplifying the equation:

2kx² - 9 = 4x - 4k - 1

2kx² - 4x - 4k + 8 = 0

To solve for x, we can use the quadratic formula. However, if the equation has infinitely many solutions, it means that the quadratic expression inside the square root in the quadratic formula must be equal to zero:

(-4)² - 4(2k)(-4k + 8) = 0

16 - 32k(-4k + 8) = 0

Now we can simplify and solve for k:

16 + 128k² - 256k = 0

128k² - 256k + 16 = 0

Dividing through by 16, we get:

8k² - 16k + 1 = 0

Now we can use the quadratic formula to solve for k:

k = (-(-16) ± √((-16)² - 4(8)(1))) / (2(8))

k = (16 ± √(256 - 32)) / (16)

k = (16 ± √224) / 16

k = (16 ± 14.966) / 16

k ≈ 3.897 or k ≈ 0.103

Therefore, the equation has infinitely many solutions when k ≈ 3.897 or k ≈ 0.103.

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