Question

A 2.00 L container will hold about 4.00 g of a gas at 180 degrees C and 1.08 atm. Calculate the molar mass for this gas.

A. 44.8 g/mol
B. 32.0 g/mol
C. 28.3 g/mol
D. 14.2 g/mol

Answer 1

To calculate the molar mass of the gas, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to convert the given temperature from Celsius to Kelvin. To do this, we add 273.15 to the temperature in Celsius:

180 degrees C + 273.15 = 453.15 K

Next, we rearrange the ideal gas law equation to solve for n (number of moles):

n = PV / RT

Given:

P = 1.08 atm

V = 2.00 L

R = 0.0821 L·atm/(mol·K)

T = 453.15 K

Plugging in the values, we have:

n = (1.08 atm) * (2.00 L) / (0.0821 L·atm/(mol·K) * 453.15 K)

Simplifying the equation, we get:

n = 0.051 mol

Finally, we can calculate the molar mass by dividing the mass of the gas by the number of moles:

molar mass = mass / moles

Given:

mass = 4.00 g

moles = 0.051 mol

Plugging in the values, we have:

molar mass = 4.00 g / 0.051 mol

Simplifying the equation, we get:

molar mass ≈ 78.43 g/mol

Therefore, the molar mass for this gas is approximately 78.43 g/mol.

Step-by-step explanation:

Ask your teacher the is something wrong somewhere with this question.

Answer 2

To calculate the molar mass of the gas, use the ideal gas law equation and the formula molar mass = mass / moles. The molar mass for this gas is approximately 40.4 g/mol.

Step-by-step explanation:

To calculate the molar mass of the gas, we can use the ideal gas law equation: PV = nRT. Rearranging the equation to solve for n, the number of moles of gas, we get:

n = PV / RT

Where P is the pressure, V is the volume, R is the ideal gas constant, and T is the temperature. Plugging in the given values:

n = (1.08 atm) * (2.00 L) / (0.0821 L*atm/mol*K) * (180 + 273 K)

Simplifying this equation gives us n ≈ 0.099 mol. To calculate the molar mass, we can use the formula:

molar mass = mass / moles.

Plugging in the values mass = 4.00 g and moles = 0.099 mol:

molar mass = 4.00 g / 0.099 mol ≈ 40.4 g/mol.

Therefore, the molar mass for this gas is approximately 40.4 g/mol, which is not one of the given answer choices. It is possible that there was an error in the question or the answer choices.