Final answer:
The specific volume of refrigerant-134a at 200 kPa and 25°C can be determined using the ideal gas law equation PV = nRT. By substituting the given values and assuming 1 mole of refrigerant-134a, we can calculate the specific volume to be approximately 0.012 m³/kPa.
Step-by-step explanation:
The specific volume of a refrigerant-134a can be determined using the ideal gas law equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.
In this case, we are given the pressure (200 kPa) and the temperature (25°C) of the refrigerant-134a. To find the specific volume, we need to find the volume. First, we convert the temperature from Celsius to Kelvin by adding 273.15: 25°C + 273.15 = 298.15 K.
Now we can use the ideal gas law equation to find the volume: V = (nRT) / P. Since we are not given the number of moles, we will assume that we have 1 mole of refrigerant-134a. We can substitute the values into the equation: V = (1 mole) * (0.008314 m³·kPa/K·mol) * (298.15 K) / (200 kPa). By performing the calculation, the specific volume is found to be approximately 0.012 m³/kPa.