201k views
2 votes
Use the shell method to write and evaluate the integral that gives the volume of the solid generated by revolving the plane region about the x-axis. x + y² = 16

User Keyanna
by
8.8k points

1 Answer

2 votes

Final answer:

To find the volume of the solid generated by revolving the plane region about the x-axis, we can use the shell method.

Step-by-step explanation:

To find the volume of the solid generated by revolving the plane region about the x-axis, we can use the shell method. First, we need to rewrite the equation in terms of y, so we have y = sqrt(16 - x). The region is bounded by the y-axis, so the limits of integration will be from 0 to the y-coordinate where the curve intersects the y-axis (which is 4).

Now, we can use the formula for the volume of a solid generated by revolving a curve about the x-axis using shells: V = 2π ∫(x * f(x)) dx, where f(x) is the radius of each shell. In this case, f(x) = sqrt(16 - x).

By plugging in the limits of integration and evaluating the integral, we can find the volume of the solid.

User Gerardo Abdo
by
8.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.