Question

A flea jumps straight up to a maximum height of 0.390 m. What is its initial velocity V₀ as it leaves the ground? Apply kinematic equations. Take the magnitude of free-fall acceleration to be 9.80 m/s². Ignore air resistance.

Answer 1

The initial velocity of the flea as it leaves the ground is 2.00 m/s.

Step-by-step explanation:

To determine the initial velocity of the flea as it leaves the ground, we can use the kinematic equations. Given that the flea jumps to a maximum height of 0.390 m, we can use the following equation: Δy = V₀t + (1/2)at², where Δy is the displacement (0.390 m), V₀ is the initial velocity, t is the time of flight, and a is the acceleration due to gravity (-9.80 m/s²).

Since the flea jumps straight up, the time of flight is equal to the time it takes for the flea to reach its maximum height and fall back down, which is twice the time it takes to reach the maximum height. Using the equation t = √((2Δy)/g), we can calculate t. Substituting this value back into the first equation, we can solve for V₀.

V₀ = Δy / t = 0.390 m / (√((2 * 0.390 m) / 9.80 m/s²)) = 2.00 m/s