Question

Trying to determine its depth, a rock climber drops a pebble into a chasm and hears the pebble strike the ground 3.90 s later. What is the duration of the pebble's fall?

Answer 1

The duration of the pebble's fall can be calculated using the equation d = (g * t^2) / 2, where d is the distance fallen, g is the acceleration due to gravity, and t is the time of fall.

Step-by-step explanation:

To calculate the duration of the pebble's fall, we can use the equation for free-fall motion:

t = √((2 * d) / g)

Where t is the time of fall, d is the distance fallen, and g is the acceleration due to gravity.

In this case, the time of fall is 3.90 s, so we need to rearrange the equation to solve for d:

d = (g * t^2) / 2

Substituting the value of g as 9.80 m/s² and the time of fall as 3.90 s, the duration of the pebble's fall is approximately 57.11 m.