Final answer:
Light B, with a wavelength of 10¹ nm, has a higher frequency than light A, which has a wavelength of 10⁴ nm, because frequency is inversely proportional to wavelength.
Step-by-step explanation:
The question asks which light has the higher frequency: light with a wavelength of 10⁴ nm (A) or light with a wavelength of 10¹ nm (B). According to the relationship between frequency and wavelength, c = λf where c is the speed of light, λ is the wavelength, and f is the frequency, as the wavelength decreases, the frequency increases. Since light B has the shorter wavelength (10¹ nm) compared to light A (10⁴ nm), light B has the higher frequency.