Final answer:
Using the stoichiometry of the reaction N₂ + 3H₂ → 2NH₃, 3.76 moles of N₂ would produce 7.52 moles of NH₃ due to the 1:2 molar ratio between N₂ and NH₃.
Step-by-step explanation:
The question asks how many moles of NH₃ can be produced from 3.76 moles of nitrogen in the reaction N₂ (g) + 3H₂ (g) → 2NH₃ (g). Using the stoichiometry of the balanced chemical equation, where one mole of N₂ reacts to form two moles of NH₃, if we start with 3.76 moles of N₂, we can produce twice that amount in moles of NH₃ because of the 1:2 molar ratio between N₂ and NH₃. Hence, the amount of NH₃ produced would be 3.76 moles of N₂ multiplied by the stoichiometric factor of 2 moles NH₃ per mole of N₂, giving us 7.52 moles of NH₃.