Question

Propose a structure for the ether of formula C₄H₁₀O with the following H NMR Signals:

1.13 (doublet, 6H)

3.65 (septet, 1H)

3.30 (singlet, 3H

Answer 1

The proposed structure for the ether compound with formula C₄H₁₀O is CH₃-CH₂-O-CH₂-CH₃.

Step-by-step explanation:

The given H NMR signals indicate the presence of three different types of hydrogen atoms in the ether compound. Let's analyze each signal:

1. 1.13 (doublet, 6H): This signal represents 6 equivalent hydrogen atoms. A doublet signal at this chemical shift suggests that these hydrogen atoms are adjacent to a carbon atom with 3 bonded hydrogens (CH3 group).
2. 3.65 (septet, 1H): This signal represents 1 hydrogen atom. A septet signal at this chemical shift indicates that this hydrogen atom is adjacent to 6 chemically equivalent hydrogen atoms.
3. 3.30 (singlet, 3H): This signal represents 3 equivalent hydrogen atoms. A singlet signal at this chemical shift suggests that these hydrogen atoms are not adjacent to any other hydrogen atoms.

Based on these signals, the proposed structure for the ether compound with formula C₄H₁₀O is:

CH3-CH2-O-CH2-CH3