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What is the normal boiling point of ethylene glycol [C₂H₆O₂] for the 34% solution and Kf =1.86 (C\m)?

Tb=79.5C
Tb=88.6C
Tb=64.3C
DOES NOT EXIST
Tb=77.5C
Tb=72.5C
Tb=84.5C
Tb=48.1C

User BlueFish
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1 Answer

6 votes

Final answer:

Without the molality of the 34% ethylene glycol solution, we cannot calculate the normal boiling point from the provided options. The equation for boiling point elevation requires both the ebullioscopic constant and the solution's molality.

Step-by-step explanation:

To find the normal boiling point of a 34% solution of ethylene glycol [C₂H₆O₂], one must consider the colligative properties of the solution. Specifically, the boiling point elevation phenomenon which states that the presence of a solute elevates the boiling point of a solvent. The normal boiling point can be calculated by using the equation ΔTb = Kb * m, where ΔTb is the boiling point elevation, Kb is the ebullioscopic constant (given as 1.86 °C/m), and m is the molality of the solution. Unfortunately, to proceed with this calculation, we would need additional information such as the molality (m) of the 34% solution, which is not provided. Given that we do not have all the necessary information, we cannot definitively determine the normal boiling point of the 34% ethylene glycol solution from the choices provided.

User Praethorian
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7.5k points