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How many fluorine atoms are present in 5.65 g of c₂f₄ ?

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Final answer:

To find the number of fluorine atoms in 5.65 g of C₂F₄, calculate the moles using the molar mass, then multiply by Avogadro's number and the number of fluorine atoms per molecule.

Step-by-step explanation:

To determine how many fluorine atoms are present in 5.65 g of C₂F₄, we need to use the molar mass and Avogadro's number. Firstly, calculate the molar mass of C₂F₄. Carbon (C) has an atomic mass of approximately 12.01 u, and fluorine (F) has an atomic mass of approximately 19.00 u. So, the molar mass of C₂F₄ is (2 × 12.01) + (4 × 19.00) = 100.02 g/mol.

Next, we can use the molar mass to find out how many moles of C₂F₄ are in 5.65 g:

moles of C₂F₄ = rac{5.65 g}{100.02 g/mol}

Subsequently, knowing that 1 mole of a substance contains 6.022 × 10²³ particles (Avogadro's number), and that each molecule of C₂F₄ has 4 fluorine atoms, we can calculate the total number of fluorine atoms:

Total fluorine atoms = moles of C₂F₄ × Avogadro's number × 4

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