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The free-fall acceleration at the surface of planet 1 is 18 m/s². The radius and the mass of planet 2 are twice those of planet 1.

What is the free-fall acceleration on planet 2?
Express your answer using two significant figures.m/s.²

User MinhHoang
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Final answer:

The free-fall acceleration on planet 2 is 9 m/s².

Step-by-step explanation:

To find the free-fall acceleration on planet 2, we can use the relationship between the radius and the mass of the planet and the free-fall acceleration. Since the radius of planet 2 is twice that of planet 1, and the mass of planet 2 is also twice that of planet 1, we can use the formula g = (G * M) / r², where G represents the gravitational constant, M represents the mass of the celestial body, and r represents the radius of the celestial body.

Let's assume the free-fall acceleration on planet 2 is a. Since the radius and mass of planet 2 are twice those of planet 1, we can write the following equation: a = (G * 2M) / (2r)². We can simplify this equation to a = (G * 2M) / 4r², which can be further simplified to a = (G * M) / 2r². This equation tells us that the free-fall acceleration on planet 2 is half that of planet 1. Therefore, the free-fall acceleration on planet 2 is 9 m/s².

User Junfei
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