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A small candle is placed on the optical axis upright in front of an unknown spherical mirror. If the magnification of the image is 2.00 and the distance between object and image is 45.0 cm, what kind of mirror is this, concave or convex? What is the focal length of such a mirror? Show your work/reasoning in detail.

User Frank Vu
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Final answer:

The mirror in question is a concave mirror with a focal length of 45 cm, inferred from the given magnification and the distance between the object and the image.

Step-by-step explanation:

To determine what kind of spherical mirror is used (concave or convex) and its focal length when a small candle is placed on its optical axis with a magnification of 2.00 and the distance between object and image is 45.0 cm, we can use the mirror equation and the magnification formula.

The mirror equation is 1/f = 1/do + 1/di, where f is the focal length, do is the object distance, and di is the image distance. The magnification m is given by -di/do for mirrors, and a positive magnification indicates a virtual image while a negative magnification indicates a real image.

Given a magnification of 2, this implies that the image is virtual and upright, hence the mirror is concave. From the magnification m = -di/do = 2, we know that di = -2do. Since the distance between the object and image is 45 cm (do + di = 45 cm), we can solve for do and di.

Substituting di = -2do into do + di = 45 cm, we get to do - 2do = -45 cm or do = 45 cm, and hence di = -90 cm. We can now use these values in the mirror equation to calculate the focal length:

1/f = 1/do + 1/di = 1/45 - 1/90 = 1/90 cm-1, so the focal length f = 90 cm / 2 = 45 cm.

Therefore, the focal length of the mirror is 45 cm, and because the image is virtual and enlarged, the mirror is concave.

User Harrison O
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