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A block of mass m/2 rests on a frictionless horizontal table, and a block of mass m rests on top of it. If the coefficient of static friction between the two blocks is µ, what is the maximum horizontal force that can be applied to the larger block before it starts to slide?

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Final answer:

The maximum horizontal force before the top block starts sliding is found by multiplying the coefficient of static friction by the gravitational force on the block. The formula is Fmax = μ*m*g, where Fmax is the maximum force, μ is the coefficient of static friction, and m*g is the weight of the top block.

Step-by-step explanation:

The student is asking about the maximum horizontal force that can be applied to the larger block before it starts sliding over the smaller block underneath it on a frictionless surface.

The maximum force of static friction, Fmax, that can act between the two blocks without causing them to slide is given by Fmax = μ*N, where μ is the coefficient of static friction and N is the normal force. For the top block of mass m, the normal force is equal to its weight, N = m*g, where g is the acceleration due to gravity. This means that the maximum horizontal force is Fmax = μ*m*g.

Applying the formula, assuming μ is given, the maximum horizontal force before sliding occurs can be calculated. It's crucial to note that this force applies to the top block only, and the combined system will move with force lower than or equal to Fmax without slipping between the blocks.

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