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Arrange the following substituted benzenes in order of increasing reactivity in electrophilic aromatic substitution (EAS):

(a) Fluorobenzene (C₆H₅F)
(b) Chlorobenzene (C₆H₅Cl)
(c) Bromobenzene (C₆H₅Br)
(d) Iodobenzene (C₆H₅I)

User PepperBob
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1 Answer

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Final answer:

The order of increasing reactivity in electrophilic aromatic substitution (EAS) for the substituted benzenes is: Iodobenzene, Bromobenzene, Chlorobenzene, Fluorobenzene.

Step-by-step explanation:

The reactivity in electrophilic aromatic substitution (EAS) can be determined by looking at the electron-withdrawing or electron-donating effects of the substituents attached to the benzene ring. Electron-withdrawing groups make the ring more reactive, while electron-donating groups make the ring less reactive.

In this case, the order of increasing reactivity in EAS for the substituted benzenes is:

  1. Iodobenzene (C₆H₅I)
  2. Bromobenzene (C₆H₅Br)
  3. Chlorobenzene (C₆H₅Cl)
  4. Fluorobenzene (C₆H₅F)

The iodine atom is the strongest electron-withdrawing group, making iodobenzene the most reactive. The reactivity decreases as you move towards fluorobenzene, which is the least reactive.

User Wojjas
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