Question

A 0.0800 kg sample of a gas is heated from 25°C to 50°C at constant pressure. If the heat capacity of the gas is 25.0 J/mol·K, what is the amount of heat absorbed by the gas?

Answer 1

The amount of heat absorbed by the gas is 50.0 Joules.

Step-by-step explanation:

To find the amount of heat absorbed by the gas, we can use the formula:

q = m * C * ΔT

where:

• q is the amount of heat absorbed
• m is the mass of the gas
• C is the heat capacity of the gas
• ΔT is the change in temperature

Given that the mass of the gas is 0.0800 kg, the heat capacity is 25.0 J/mol·K, and the change in temperature is 50°C - 25°C = 25 K, we can substitute these values into the formula:

q = 0.0800 kg * 25.0 J/mol·K * 25 K

Simplifying the expression:

q = 50.0 J

Therefore, the amount of heat absorbed by the gas is 50.0 Joules.