Question

How many moles of H₂O can be formed from 2.67 × 10²³ molecules of NH₃ from the following equation? 4 NH₃(g) + 5 O₂(g) → 4 NO(g) + 6 H₂O(g)

a) 2.67 × 10²³ moles
b) 1.78 × 10²³ moles
c) 4.45 × 10²³ moles
d) 3.56 × 10²³ moles

Answer 1

Approximately 0.67 moles of H2O can be formed from 2.67 × 10^23 molecules of NH3 according to the stoichiometry of the chemical equation provided.

Step-by-step explanation:

To determine how many moles of H2O can be formed from 2.67 × 1023 molecules of NH3, we first need to use Avogadro's number to convert molecules to moles. Avogadro's number is 6.022 × 1023 molecules per mole, so:

Number of moles of NH3 = (2.67 × 1023 molecules NH3) / (6.022 × 1023 molecules/mole)

Number of moles of NH3 = 0.4435 moles NH3

Now, according to the balanced chemical equation 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g), 4 moles of NH3 produce 6 moles of H2O. Therefore, we can set up a proportion:

(0.4435 moles NH3) × (6 moles H2O / 4 moles NH3) = 0.6653 moles H2O

Therefore, the answer is approximately 0.6653 moles of H2O, which can be rounded to two significant figures, yielding 0.67 moles of H2O, represented here as option (a).