Final answer:
The force experienced by a charge of 3.0 µC in an electric field strength of 5.10×104 N/C is 0.153 N. This calculation is based on the formula F = qE.
Step-by-step explanation:
Force Experienced by a Charge in an Electric Field
The force experienced by a charge placed in an electric field is given by the equation F = qE, where 'F' is the force in newtons (N), 'q' is the charge in coulombs (C), and 'E' is the electric field strength in newtons per coulomb (N/C) or volts per meter (V/m).
Given a charge of 3.0 µC (microcoulombs), we first convert it to coulombs: 3.0 µC = 3.0 × 10-6 C. The electric field strength is given as 5.10×104 N/C.
To find the force, we use the formula:
F = qE = (3.0 × 10-6 C) × (5.10×104 N/C) = 15.3 × 10-2 N = 0.153 N.
Therefore, the force experienced by the charge is 0.153 N, which does not match any of the provided options (a) 33 N, (b) 11 N, (c) 66 N, or (d) 22 N.