Question

Object A, which has been charged to + 12 nC , is at the origin. Object B, which has been charged to − 28 nC , is at (x,y)=(0.0cm,2.0cm).What is the magnitude of the electric force on object A? and What is the magnitude of the electric force on object B?

Answer 1

The magnitude of the electric force on Object A can be found using Coulomb's Law, which states that the magnitude of the electric force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. The same equation can be used to calculate the magnitude of the electric force on Object B.

Step-by-step explanation:

The magnitude of the electric force on Object A can be found using Coulomb's Law. Coulomb's Law states that the magnitude of the electric force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Using Coulomb's Law, we can calculate the magnitude of the electric force on Object A:

1. Calculate the distance between Object A and Object B. In this case, the distance is 2 cm.
2. Plug the values into Coulomb's Law equation:
   F = (k * q1 * q2) / r^2
   Where F is the magnitude of the electric force, k is Coulomb's constant (8.99 x 10^9 Nm^2/C^2), q1 is the charge of Object A (12 nC), q2 is the charge of Object B (-28 nC), and r is the distance between the objects (2 cm).
3. Calculate the magnitude of the electric force using the equation.

Similarly, you can calculate the magnitude of the electric force on Object B by swapping the charges in the equation.