227k views
1 vote
If a = 7 × 10 ⁻⁶ C/m and b = 1 m, find E at r = 0.6 m⁴. The permittivity of a vacuum is 8.8542 × 10 ⁻¹² C² /N · m² .

User Mbgda
by
8.5k points

1 Answer

5 votes

Final answer:

To calculate the electric field (E) at 0.6 m from a uniformly charged line with charge density of 7 × 10⁻⁶ C/m, use the expression E = (1/(2πε₀)) * (λ/r), substituting the given values and permittivity of free space.

Step-by-step explanation:

The student has asked for the electric field (E) at a distance of r = 0.6 m from a uniformly charged line with linear charge density a = 7 × 10⁻⁶ C/m. This is a classic physics problem involving the use of Coulomb's Law and the concept of electric field due to a continuous charge distribution. The permittivity of free space (ε₀) is given as 8.8542 × 10⁻¹² C²/N · m².

The general expression for the electric field (E) at a distance r from an infinitely long straight wire with uniform linear charge density λ, in a vacuum, is given by:

E = (1 / (2πε₀)) * (λ / r)

Substituting the given values:

E = (1 / (2π * 8.8542 × 10⁻¹² C²/N · m²)) * (7 × 10⁻⁶ C/m / 0.6 m)

Calculating the above expression will yield the magnitude of the electric field at the specified distance from the charged line.

User Afilina
by
8.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.