Question

a major league pitcher can throw a baseball in excess of 46.0 m/s. if a ball is thrown horizontally at this speed, how much will it drop by the time it reaches the catcher who is 16.7 m away from the point of release?

Answer 1

The ball's vertical displacement 0.64 m

Step-by-step explanation:

Given:

V₀ = 46.0 m

D = 16.7 m

g = 9.8 m/s²

____________

ΔH - ?

Time:

t = D / V₀ = 16.7 / 46.0 ≈ 0.36 s

Vertical displacement:

ΔH = g·t² / 2

ΔH = 9.8·0.36² / 2 ≈ 0.64 m