Final answer:
To find the vapor pressure of a NaCl solution, Raoult's law is used, which involves the vapor pressure of pure water and the mole fractions of the components in the solution. Details specific to solving the given problem are not provided, but the method typically includes calculating moles of both solute and solvent.
Step-by-step explanation:
The question asks to calculate the vapor pressure of a NaCl solution after dissolving 90.0 g NaCl in 250.0 g of water at 25°C, given the vapor pressure of pure water at 25°C is 23.56 torr. To solve this, we need to use Raoult's law, which states that the vapor pressure of the solution (Psolution) is equal to the vapor pressure of the pure solvent (Psolvent) multiplied by the mole fraction of the solvent (Xsolvent). However, the details to solve this particular problem are not provided, so we will talk generally about the process. We would need to calculate the quantity in moles of NaCl and the quantity in moles of water to find the mole fractions. Because NaCl is an electrolyte, it dissociates in water, contributing twice the number of particles, which impacts the colligative property of vapor pressure reduction. Once we have the mole fractions, we apply Raoult's law to find the vapor pressure of the solution.