Question

The formula h(t) = -16t² + 32t + 80 gives the height, h, above the ground, in feet, of an object thrown, at t = 0, upward from the top of an 80 foot building. What is the height of the object at t = 2 seconds?

Answer 1

The height of the object at 2 seconds is 80 feet above the ground, as calculated by plugging t=2 into the given quadratic equation.

Step-by-step explanation:

The question is asking for the height of an object after 2 seconds when the object's height is given by the quadratic equation h(t) = -16t² + 32t + 80. To find the height at t = 2 seconds, we plug in the value of t into the equation:

h(2) = -16(2)² + 32(2) + 80 = -64 + 64 + 80 = 80 feet.

Therefore, the object's height at 2 seconds is 80 feet above the ground.