Question

The electric field 5.30 cm from a very long charged wire is (2100 N/C toward the wire).

what is the charge (in nc ) on a 1.00-cm-long segment of the wire?

Answer 1

To find the charge on a 1.00-cm-long segment of the wire, we can use the formula E = k(Q/L), where E is the electric field, k is the electrostatic constant, Q is the charge, and L is the length of the wire segment. Plugging in the given values, we can solve for Q.

Step-by-step explanation:

To find the charge on a 1.00-cm-long segment of the wire, we need to use the formula for electric field:

E = k(Q/L)

Where E is the electric field, k is the electrostatic constant (9.0 x 10^9 Nm^2/C^2), Q is the charge, and L is the length of the wire segment.

From the given information, we know that the electric field is 2100 N/C, and the distance from the wire is 5.30 cm. Plugging these values into the equation, we can solve for Q:

2100 = (9.0 x 10^9)(Q/0.01)

Simplifying the equation, we can find that Q, the charge on the wire segment, is 1.89 x 10^-5 Coulombs (C).