Question

What is the complete ionic equation for the reaction 2KOH(aq) + H₂SO₄(aq) → 2H₂O(l) + K₂SO₄(aq)?

1) 2KOH + H₂SO₄ → 2H₂O + K₂SO₄
2) 2KOH⁻ + 2HSO₄- → 2H₂O(l) + 2KSO₄-
3) OH⁻ + 2H+ → 2H₂O(l)
4) 2KOH⁻ + H₂SO₄ + OH⁻ + 2H+ → 2H₂O + K₂SO₄

Answer 1

The complete ionic equation for the reaction 2KOH(aq) + H₂SO₄(aq) → 2H₂O(l) + K₂SO₄(aq) is: 3) OH⁻ + 2H⁺ → 2H₂O(l). This equation represents the dissociation of the potassium hydroxide (KOH) and sulfuric acid (H₂SO₄) into their respective ions in solution. The hydroxide ion (OH⁻) reacts with the hydrogen ion (H⁺) to form water (H₂O) in the reaction.

Step-by-step explanation:

The complete ionic equation for the reaction 2KOH(aq) + H₂SO₄(aq) → 2H₂O(l) + K₂SO₄(aq) is:

3) OH⁻ + 2H⁺ → 2H₂O(l)

This equation represents the dissociation of the potassium hydroxide (KOH) and sulfuric acid (H₂SO₄) into their respective ions in solution. The hydroxide ion (OH⁻) reacts with the hydrogen ion (H⁺) to form water (H₂O) in the reaction.