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What is the impulse that occurs when an average force of 10 N is exerted on a cart for 3.0 s?

User Happyfirst
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Final answer:

The impulse that occurs when an average force of 10 N is exerted on a cart for 3.0 s is 30 N.s.

Step-by-step explanation:

The impulse that occurs when an average force of 10 N is exerted on a cart for 3.0 s can be calculated using the formula:

Impulse = Force x time

Using the given values:

Impulse = 10 N x 3.0 s = 30 N.s

Therefore, the impulse that occurs is 30 N.s.

User Shaneen
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