Question

if an object's recorded motion on a number line moved from x=12 to x=124m and back to x=98m and the total time interval for this motion was 10s, then what was the object's average velocity?

Answer 1

The average velocity of an object that moves from x=12m to x=98m over a 10-second period is 8.6 m/s, which is calculated by dividing the total displacement by the total time.

Step-by-step explanation:

To calculate the average velocity of an object, we can use the formula:

Average velocity (ū) = Displacement (Δx) / Elapsed time (Δt)

Displacement is defined as the change in position, so for this problem we look at the initial and final positions on the number line. The object starts at x=12m and ends up at x=98m. Thus, the displacement is:

98m - 12m = 86m

Since the total time interval given is 10 seconds, we then divide the displacement by this time to get the average velocity:

86m / 10s = 8.6 m/s

This value is representative of the object's overall change in position per unit of time over the 10-second interval, regardless of any intermediate motion it might have made (like moving to x=124m before going back to x=98m).