Final answer:
The electric field just above the surface of a large sheet with a uniform charge density of 10 μC/m2 is calculated using Gauss's Law to be 5.65 x 10^5 N/C.
Step-by-step explanation:
The question asks about the electric field generated by a large sheet of charge with a known uniform charge density. The electric field (E) created by a sheet of charge can be calculated using Gauss's Law. For a sheet with charge density σ (sigma), the electric field is given by E = σ / (2ε0), where ε0 is the vacuum permittivity. In this case, the charge density is 10 μC/m2 (microcoulombs per square meter), so we can plug this value into the formula.
The vacuum permittivity ε0 is a known constant (approximately 8.85 x 10-12 C2/N·m2). Consequently, the electric field just above the surface of the sheet is E = (10 x 10-6 C/m2) / (2 x 8.85 x 10-12 C2/N·m2) = 5.65 x 105 N/C, directed away from the sheet if the charge is positive, or towards the sheet if the charge is negative.