Final answer:
The net ionic equation for the reaction between excess hydrochloric acid and sodium sulfide is H+(aq) + S2-(aq) → H2S(g), where hydrogen ions react with sulfide ions to produce hydrogen sulfide gas.
Step-by-step explanation:
The question asks for the net ionic equation when excess hydrochloric acid (HCl) is combined with sodium sulfide (Na2S) in aqueous solution. The products of this reaction are sodium chloride (NaCl) and hydrogen sulfide gas (H2S). However, there seems to be some confusion as the example reactions provided are for the neutralization reaction between sodium hydroxide (NaOH) and hydrochloric acid, which is not the reaction in question.
When sodium sulfide reacts with hydrochloric acid, the balanced molecular equation is:
Na2S(aq) + 2 HCl(aq) → 2 NaCl(aq) + H2S(g)
The full ionic equation is:
2 Na+(aq) + S2-(aq) + 2 H+(aq) + 2 Cl-(aq) → 2 Na+(aq) + 2 Cl-(aq) + H2S(g)
The sodium and chloride ions are spectator ions, so they can be removed to find the net ionic equation:
H+(aq) + S2-(aq) → H2S(g)