Final answer:
The molecule N≡C-CH-O has a total of 5 sigma (σ) bonds and 3 pi (π) bonds, with the triple bond contributing 1 σ and 2 π bonds, and the double bond contributing 1 σ and 1 π bond.
Step-by-step explanation:
For the molecule with the structure N≡C-CH-O (where there is a nitrogen-carbon triple bond and a carbon-oxygen double bond), we can determine the number of σ (sigma) and π (pi) bonds. A triple bond between two atoms consists of one sigma bond and two pi bonds, and a double bond consists of one sigma bond and one pi bond.
Therefore, in the nitrogen-carbon triple bond, there is 1 σ bond and 2 π bonds. In the carbon-oxygen double bond, there is 1 σ bond and 1 π bond. Lastly, the single bonds present in the molecule (N-C and C-H) are all sigma bonds. Assuming there is one hydrogen atom, we have three additional σ bonds from these single bonds (one from N-C and two from two C-H bonds).
Counting them together, the total is 5 σ bonds (1 from N≡C, 1 from C=O, 1 from N-C, and 2 from C-H) and 3 π bonds (2 from N≡C and 1 from C=O).