Final answer:
The electric field strength 8.0 mm from a proton or electron is 1.439 x 10^5 N/C. From a proton, the field direction is away, whereas from an electron, it is towards the charge.
Step-by-step explanation:
The strength of the electric field (Ep) 8.0 mm from a proton can be calculated using Coulomb's law, which states that the electric field (E) due to a point charge (q) at a distance (r) is given by E = k * |q| /r^2, where k is Coulomb's constant (8.9875517873681764 × 10^9 N m^2/C^2), and q is the charge of the proton (1.602 × 10^-19 C).
A.) To calculate the strength of the electric field Ep 8.0 mm (or 8.0 × 10^-3 meters) from a proton:
E = (8.987551787 × 10^9 N m^2/C^2) × (1.602 × 10^-19 C) / (8.0 × 10^-3 m)^2
E = 1.439 × 10^5 N/C
B.) The direction of the electric field (Ep) from a proton is always away from the proton, as a proton has a positive charge.
C.) The strength of the electric field (Ee) from an electron at the same distance is equal in magnitude to that from a proton because they have equal but opposite charges, so Ee = Ep = 1.439 × 10^5 N/C.
D.) The direction of the electric field (Ee) from an electron is towards the electron, since an electron has a negative charge.