Question

When 1.60 x 10⁵ j of heat transfer occurs into a meat pie initially at 23.5 degree c, what is the final temperature of the meat pie if its specific heat capacity is 4.18 J/g°C and its mass is 200 g?

Answer 1

The final temperature of the meat pie after the heat transfer of 1.60 x 10⁵ J occurs and its initial temperature was 23.5°C, is 214.9°C.

Step-by-step explanation:

To determine the final temperature of the meat pie, we can use the formula for heat transfer, Q = mcΔT, where Q is the heat transfer, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. We are given that Q is 1.60 x 10⁵ J, m is 200 g, and c is 4.18 J/g°C. The initial temperature is given as 23.5°C.

First, we must convert the mass to kilograms by dividing by 1000, so m = 0.200 kg. Plugging the values into the formula and solving for ΔT, we get:
ΔT = Q / (mc) = (1.60 x 10⁵ J) / (0.200 kg * 4.18 J/g°C * 1000 g/kg) = 191.3875598°C.

Adding the change in temperature to the initial temperature gives us the final temperature:
23.5°C + 191.4°C = 214.9°C.